Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

In 1 gm of a solid, there are 5\times 10^{21} atoms. If one electron is removed from everyone of 0.01% atoms of the solid, the charge gained by the solid is (given that electronic charge is 1.6\times 10^{-19}C  )

  • Option 1)

    + 0.08 C

  • Option 2)

    + 0.8 C

  • Option 3)

    - 0.08 C

  • Option 4)

    - 0.8 C

 

Answers (1)

best_answer

As we learned

Quantization of charge -

Charge on any body will be some integral multiple of e.

 

- wherein

Q=\pm ne

n = 1, 2, 3, ......

 

 To calculate charge, we will apply formula Q = ne for this, we must have number of electrons. Here, number of electrons n=.01\; ^{0}/_{0}\; \; of \; 5\times 10^{21}

i.e   n=\frac{5\times 10^{21}\times .01}{100}=5\times 10^{21}\times10^{-4}=5\times 10^{17}

So   Q=5\times 10^{17}\times 1.6\times 10^{-19}=8\times 10^{-2}=0.08\; C

Since electrons have been removed, charge will be positive i.e Q = + 0.08 C

 


Option 1)

+ 0.08 C

Option 2)

+ 0.8 C

Option 3)

- 0.08 C

Option 4)

- 0.8 C

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question