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  • Solve this problem - Limit , continuity and differentiability - JEE Main-13

Let y= \cos (3x-1) then dy/dx equals 

  • Option 1)

    3 \sin (3x-1)

  • Option 2)

    -3 \sin (3x-1)

  • Option 3)

    -\sin (3x-1)

  • Option 4)

    \sin (3x-1)

 

Answers (1)

best_answer

As we have learned 

Chain Rule for differentiation (direct) -

Let\;\;y=sin(ax+b)
 

\therefore\:\:\frac{dy}{dx} =\frac{dsin(ax+b)}{d(ax+b)}\times \frac{d(ax+b)}{dx}


=cos(ax+b)\times a

=a\;cos(ax+b)

- wherein

Where derivative of sin (ax + b) with respect to (ax + b)  and the derivative of (ax + b)  with respect to  x.

 

 \frac{d(\cos (3x-1))}{dx} = \frac{d(\cos (3x-1))}{d(3x-1)}\times \frac{d(3x-1)}{dx}

= -\sin (3x-1)\times 3= -3 \sin (3x-1)

 

 

 

 


Option 1)

3 \sin (3x-1)

Option 2)

-3 \sin (3x-1)

Option 3)

-\sin (3x-1)

Option 4)

\sin (3x-1)

Posted by

Himanshu

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