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  • Solve this problem - Limit , continuity and differentiability - JEE Main-21

Point of inflexion for f(x) = x^3 is at x equals

  • Option 1)

    -1

  • Option 2)

    \frac{1}{}2

  • Option 3)

    0

  • Option 4)

    1

 

Answers (1)

best_answer

As we have learned

Condition for inflexion -

1.  f''(x) changes sign x passes through the point  a.

2.  only those values of  x  for  f''(x)  change signs are points of inflexion.

ex:\:\:\:f''(x)=x^{2}(x-2),\:\:\:f''(x)=0

at\:\:\:x=0\:\:and\:\:x=2\:\:\:but\:only\:\:\:x=2  point\:of\:inflexion\:because\:at\:x=2\:\:\:f''(x)\:\:changes\:sign\:only

-

 

f'(x)=3x^{2}\Rightarrow f''(x) = 6x which will change its sign at x= 0, so concavity will change at x=0 , so x=0 is a point of inflection  

 

 

 

 


Option 1)

-1

Option 2)

\frac{1}{}2

Option 3)

0

Option 4)

1

Posted by

Himanshu

View full answer

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