#### In a Young’s double slit experiment with light of wavelength the separation of slits is d and distance of screen is D such that D > > d > >. If the Fringe width is , the distance from point of maximum intensity to the point where intensity falls to half of maximum intensity on either side is : Option 1) Option 2) Option 3) Option 4)

As we learnt in

Malus Law -

angle made by E vector with transmission axis.

- wherein

Intensity of transmitted light after polarisation .

Intensity of  incident light.

Fringe Width -

- wherein

Distance of

Maxima

Distance of

maxima

Here

so

(i)

(ii)

Thefore,    from equation (i) and (ii)

Correct option is 2.

Option 1)

This is an incorrect option.

Option 2)

This is the correct option.

Option 3)

This is an incorrect option.

Option 4)

This is an incorrect option.