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  • Solve this problem - The complex that has highest crystal field splitting energy, is: - Co-ordination Compounds - JEE Main

The complex that has highest crystal field splitting energy (\Delta ), is:

  • Option 1)

    [Co(NH_{3})_{5}Cl]Cl_{2}

     

  • Option 2)

    [Co(NH_{3})_{5}(H_{2}O)]Cl_{3}

  • Option 3)

    K_{3}[Co(CN)_{6}]

  • Option 4)

    K_{2}[CoCl_{4}]

Answers (1)

best_answer

 

CFSE in tetrahedral complexes -

CFSE = \left [-\frac{3}{5}\left ( No.\;of\;electron\;in\;e \right )+\frac{2}{5}\left ( No.\;of\;\acute{e}\;in\; t_{2}\right ) \right ] \bigtriangleup t

-

 

 

CFSE in octahedral complex -

CFSE =\left [- \frac{2}{5}\left ( No. of\;electron\;in\;t_{2}g \right ) +\frac{3}{5}\left ( No. of\;\acute{e}s\;in\;eg \right ) \right ]\bigtriangleup \circ

 

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Crystal Field Theory -

According to this theory, metal and ligand are considered as point charges. This theory deals with electrostatic force of attraction means the talks about the ionic character of M-L bond. 

-

K_{3}\left [ CO\left ( CN \right )_{6}\right ]have CN- ligands which is strongfield ligand among the given ligand in otther complexes.

  


Option 1)

[Co(NH_{3})_{5}Cl]Cl_{2}

 

Option 2)

[Co(NH_{3})_{5}(H_{2}O)]Cl_{3}

Option 3)

K_{3}[Co(CN)_{6}]

Option 4)

K_{2}[CoCl_{4}]

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