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Sound travels in a mixture of two moles of helium and \mathrm{n} moles of hydrogen. If rms speed of gas molecules in the mixture is \mathrm{\sqrt{2}} times the speed of sound, then the value of \mathrm{n} will be :

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

For non-reacting gaseous mixture

\mathrm{\frac{n_{\text {mix }}}{v_{\text {mix }}-1}=\frac{n_1}{v_1-1}+\frac{n_2}{r_2-1} }

\mathrm{\frac{2+n}{V_{\text {mix }}-1}=\frac{2}{\left(\frac{5}{3}-1\right)}+\frac{n}{\left(\frac{7}{5}-1\right)} }

\mathrm{\frac{2+n}{V_{\text {mix }}-1}=3+\frac{5}{2} n \rightarrow (1)}

\mathrm{R_{m s} \text { speed of gas molecules }=\sqrt{\frac{3 R T}{M}}}

\mathrm{\text { Speed of sound }=\sqrt{\frac{ VR T}{M}}}

\mathrm{\sqrt{\frac{3 R T}{M}}=\sqrt{\frac{V R T}{M}} \times \sqrt{2}(\text { Given })}

\mathrm{2 V=3}

\mathrm{V_{\text {mix }}=V^2=\frac{3}{2} \rightarrow \text { (2) }}

\mathrm{\frac{2+n}{\frac{1}{2}}=3+\frac{5 n}{2}} (from eq 1 & 2)

\mathrm{4+2 n=3+\frac{5}{2} n}

\mathrm{1=\frac{n}{2}}

\mathrm{n=2}

Hence (2) is correct option.

 












 

Posted by

Sumit Saini

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