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South African cricket captain lost the toss of a coin 13 times out of 14. The chance of this happening was

Option: 1

\frac{7}{2^{13}}


Option: 2

\frac{1}{2^{13}}


Option: 3

\frac{13}{2^{14}}


Option: 4

\frac{13}{2^{13}}


Answers (1)

best_answer

As we have learnt in

 

Binomial Theorem on Probability -

Then

\dpi{100} P\left ( X= r \right )     or   P(r)

=\ ^{n}C_{\Upsilon }\cdot P^{r }\cdot q^{n-r}

-

 

 

P=^{14}C_{13}\;\left ( \frac{1}{2} \right )^{13}\left ( \frac{1}{2} \right )^{14-13}=14\times \frac{1}{2^{13}}\frac{1}{2}=\frac{7}{2^{13}}

Posted by

manish painkra

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