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When bodies are projected from the earth surface with velocity \sqrt3 times of escape velocity (v_{e}) then find its speed in interstellar space.

Option: 1

\sqrt{2}v_{e}


Option: 2

2 \ v_{e}


Option: 3

2\sqrt{2}v_{e}


Option: 4

\frac{v_{e}}{\sqrt2}


Answers (1)

best_answer

As we learn

Body projected with velocity greater than escape velocity -

{V}'=\sqrt{V^{2}-V_{e}^{2}}

new velocity of body= {V}'

V\rightarrow projection velocity

V_{e}\rightarrow Escape velocity

- wherein

Body will move in interplanetery or interstellar space with  \sqrt{V^{2}-V_{e}^{2}} = velocity

 

 speed in intersetellar space v' = \sqrt{v^{2}-v_{e}^{2}}

As v=\sqrt{3}v_{e}

v' = \sqrt{(\sqrt{3v_{e}})^{2}-v_{e}^{2}} = \sqrt{2v_{e}^{2}} = \sqrt{2}v_{e}

 

 

Posted by

Sanket Gandhi

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