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A radioactive nucleus X decays to a stable Y. Then time graph of rate formation of Y against t will be

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As we learn

Radioactivity -

A=-\frac{dN}{dt}

- wherein

Activity is measured in terms of disintegration per second

Its SI unit is 'Becquerel'

 

 N=N_{0}\cdot e^{-\lambda t}

N_{Y}=N_{0}\left ( 1- e^{-\lambda t} \right )

Rate of formation of Y is

\frac{dN}{dt}=+\lambda N_{0} e^{-\lambda t}

Which decreases exponentially with time.

 

Posted by

Ritika Kankaria

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