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An aeroplane is flying horizontally with a velocity of 100m/s at a height of 500m when it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is  (g = 9.8 m/s2)

 

Option: 1

1 km


Option: 2

1.5 km


Option: 3

0.5 km

 


Option: 4

1.2 km


Answers (1)

 

  1. Time of flight

  • Formula

               t= \sqrt{\frac{2h}{g}}

           where   t= time of flight

                        h= Height from which projectile is projected

 

  1. Range of projectile

  • Formula

                      R= u .\sqrt{\frac{2h}{g}}

           Where R= Range of projectile

           u= horizontal velocity of projection from height h

So,

\\y=\frac{1}{2}gT^{2}\\* 500= \frac{1}{2}\times 10\times t^{2}\Rightarrow t= 10 Sec\\* horizontal \: \: range \: \: AB= \left ( U_{x}\times T \right )\\* =100\times 10= 1000m

Posted by

Ramraj Saini

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