A load of mass 100 gm increases the length of wire by 10 cm. If the system is kept in oscillation, its time period is

  • Option 1)

    0.314 s

  • Option 2)

    3.14 s

  • Option 3)

    0.628 s

  • Option 4)

    6.28 s

 

Answers (1)

As we discussed in

Time period of oscillation for spring mass system -

T= 2\pi \sqrt{\frac{m}{K}}

- wherein

m = mass of block

K = spring constant

 

 T=2\Pi \sqrt{\frac{m}{k}}

F=mg=kx = k=\frac{mg}{x}

T=2\pi \sqrt{\frac{mx}{mg}} = T= 2\pi\sqrt{\frac{x}{g}}

Given \: x=10cm =10\times 10^{-2}mt

T=2\pi \sqrt{\frac{10\times 10^{-2}}{10}}

After calculating we get

T= 0.628 sec


Option 1)

0.314 s

Incorrect

Option 2)

3.14 s

Incorrect

Option 3)

0.628 s

Correct

Option 4)

6.28 s

Incorrect

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