Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Stuck here, help me understand: A load of mass 100 gm increases the length of wire by 10 cm. If the system is kept in oscillation, its time period is

A load of mass 100 gm increases the length of wire by 10 cm. If the system is kept in oscillation, its time period is

  • Option 1)

    0.314 s

  • Option 2)

    3.14 s

  • Option 3)

    0.628 s

  • Option 4)

    6.28 s

 

Answers (1)

best_answer

As we discussed in

Time period of oscillation for spring mass system -

T= 2\pi \sqrt{\frac{m}{K}}

- wherein

m = mass of block

K = spring constant

 

 T=2\Pi \sqrt{\frac{m}{k}}

F=mg=kx = k=\frac{mg}{x}

T=2\pi \sqrt{\frac{mx}{mg}} = T= 2\pi\sqrt{\frac{x}{g}}

Given \: x=10cm =10\times 10^{-2}mt

T=2\pi \sqrt{\frac{10\times 10^{-2}}{10}}

After calculating we get

T= 0.628 sec


Option 1)

0.314 s

Incorrect

Option 2)

3.14 s

Incorrect

Option 3)

0.628 s

Correct

Option 4)

6.28 s

Incorrect

Posted by

Aadil

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2024 application correction facility begins tomorrow; editable fields
anam-khan

BITSAT 2024 registration window closes tomorrow; exam from May 20
anam-khan

BITSAT 2024 registration deadline extended till April 16; session 1 exam from May 19 to 24

Latest Question