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 A 1\mu F capacitor and a 2\mu F capacitor are connected in parallel across a 1200 volts line. The charged capacitors are then disconnected from the line and from each other. These two capacitors are now connected to each other in parallel with terminals of unlike signs together. The charges on the capacitors will now be

  • Option 1)

    1800 \mu C

  • Option 2)

    400 \mu C ..and..800 \mu C

  • Option 3)

    800\mu C .. and ..400 \mu C .

  • Option 4)

    800 \mu C ..and.. 800 \mu C

 

Answers (1)

Initially charge on capacitors can be calculated as follows 
        
    Q1 = 1 × 1200 = 1200 C and Q2 = 2 × 1200 = 2400 C
Finally when battery is disconnected and unlike plates are connected together then common potential    

V'=\frac{Q_2-Q_1}{C_1+C_2}=\frac{2400-1200}{1+2}=400V

Hence, New charge on   is  C_1   is  1 * 400 = 400\mu C 
And New charge on    C_2 is 2*400 = 800\mu C

Posted by

Safeer PP

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