Get Answers to all your Questions

header-bg qa

The  pK_{a} of a weak acid \left ( HA \right )is 4,5.The pOH of an aqueous bufferd solution of HA in which 50% of  the acid is ionized is

  • Option 1)

    7.0

  • Option 2)

    4.5

  • Option 3)

    2.5

  • Option 4)

    9.5

 

Answers (1)

best_answer

As we learnt in 

Buffer Solutions -

The solutions which resist change in pH on dilution or with addition of small amounts of acid or alkali are called buffer solution.  

- wherein

Many body fluids  e.g.  blood

 

 and

 

p(Kw) -

K_{w}=[H_{2}O^{+}]\:[H\bar{O}]=10^{-14}

Although  K_{w}  may change with temperature the variation in pH with temperature are so small that we often ignore it.

- wherein

p(K_{w})=-logK_{w}

               =-log{[H_{3}O^{+}]\:[\bar{O}H]}

               =-log10^{-14}

p(K_{w})=p(H)+p(OH)

                 =14

 

 

For acidic buffer,   pH=pK_{a}+log\, \frac{\left [ A^{-} \right ]}{\left [ HA \right ]}

When the acid is 50% dissociated , \left [ A^{-} \right ]=\left [ HA \right ]

or\; \; \; pH=pK_{a}+log1\; \; \; or\; \; pH=pK_{a}

Given\; \; pK_{a}=4.5\; \; \therefore pH=4.5

\therefore \; \; pOH=14-4.5=9.5


Option 1)

7.0

This option is incorrect

Option 2)

4.5

This option is incorrect

Option 3)

2.5

This option is incorrect

Option 4)

9.5

This option is correct

Posted by

prateek

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE