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  • Stuck here, help me understand: - Limit , continuity and differentiability - JEE Main-15

Length of substangent at a point  y = x^2 + 1 can be ?

  • Option 1)

    \frac{1}{4}

  • Option 2)

    \frac{1}{}3

  • Option 3)

    \frac{1}{}9

  • Option 4)

    2

 

Answers (1)

best_answer

As we hyave learned

Length of sub Tangent -

L_{ST}=\frac{y}{y'}

- wherein

Where \:\:\:y'=\frac{dy}{dx}

 

 Length of subtangent = y/y'=\frac{x^{2}+1}{2x} =1/2 (x+1/x)  

we know (x+1/x) is either \leq -2 .. or .. (x+1/x)\geq 2

\Rightarrow 1/2 (x+1/x) \leq -1 .. or.. 1/2(x+1/x)\geq 1\Rightarrow min 1/2(x+1/x)=1

 

 

 

 

 


Option 1)

\frac{1}{4}

Option 2)

\frac{1}{}3

Option 3)

\frac{1}{}9

Option 4)

2

Posted by

Himanshu

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