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  • Stuck here, help me understand: - Redox Reaction and Electrochemistry - JEE Main-2

What will be the % change in molar conductivity if the concentration is changed from 0 to 1. A =\frac{1}{2}\Lambda^{o}

  • Option 1)

    -50%

  • Option 2)

    -100%

  • Option 3)

    -75%

  • Option 4)

    -25%

 

Answers (1)

best_answer

As we have learnt,

 

Variation of Molar Conductivity in strong electrolyte -

\Lambda m=\Lambda^{0} m-AC^{\frac{1}{2}}

- wherein

For strong electrolyte, \Lambda m increases slowly with dilution.

 

 \Lambda_m = \Lambda^o - A C^{\frac{1}{2}} \\*\Rightarrow \Lambda_{mi} = \Lambda^{0}_m \\* \Lambda_{mf} = \Lambda_m^o -\frac{\Lambda_m^o}{2}\times 1 = \frac{\Lambda_m^o}{2} \\*\therefore \%\;change = \frac{-\frac{\Lambda_m^o}{2}}{\Lambda_m^o}\times 100 = -50\%

 


Option 1)

-50%

Option 2)

-100%

Option 3)

-75%

Option 4)

-25%

Posted by

Aadil

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