Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Tell me? An infinitely long current carrying wire and a small current carrying loop are in the plane of the paper as shown. The radius of the loop is a and distance of its centre from the wire is d (d>>a). If the loop applies a force F on the wire t

An infinitely long current carrying wire and a small current carrying loop are in the plane of the paper as shown. The radius of the loop is a and distance of its centre from the wire is d (d>>a). If the loop applies a force F on the wire then :

 

  • Option 1)

    F=0\: \:

  • Option 2)

    F\alpha \left ( \frac{a}{d} \right )\: \:

  • Option 3)

    F\alpha \left ( \frac{a^{2}}{d^{3}} \right )\; \;

  • Option 4)

    F\alpha \left ( \frac{a}{d} \right )^{2}

Answers (1)

best_answer

 

Magnetic field -

B=\frac{F}{m_{0}}

=B=\frac{\mu _{0}}{4\pi } \frac{m}{d^{2}}

 

-

Equivalent dipole of given loop = m\frac{dB}{dr}

\frac{dB}{dx} = \frac{d}{dx} \left ( \frac{\mu _{0} I}{2 \pi x} \right )

\alpha \frac{1}{x^{2}}

\therefore equivalent \ \ dipole \ \ \alpha \frac{M}{x^{2}}

\alpha \frac{a^{2}}{x^{2}}

Since M = NIA

So M \alpha a2

 


Option 1)

F=0\: \:

Option 2)

F\alpha \left ( \frac{a}{d} \right )\: \:

Option 3)

F\alpha \left ( \frac{a^{2}}{d^{3}} \right )\; \;

Option 4)

F\alpha \left ( \frac{a}{d} \right )^{2}
Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Result 2024 Live: JEE Mains session 2 results at jeemain.nta.ac.in soon; rank predictor
anam-khan

JEE Main 2024 session 2 final answer key out at jeemain.nta.ac.in; steps to check probable scores
anam-khan

JEE Main Result 2024 Live: Download session 2 final answer key at jeemain.nta.ac.in; rank predictor, cutoff

Latest Question