Get Answers to all your Questions

header-bg qa

Electric field due to charge cylinder at a distance r will be (If cylinder is non cunducting, Radius given is R)

  • Option 1)

    \frac{\lambda}{2\pi\epsilon_0 R}

  • Option 2)

    \frac{\lambda}{2\pi\epsilon_0 }\log_e r + c

  • Option 3)

    0

  • Option 4)

    \frac{\lambda}{2\pi\epsilon_0 r}

 

Answers (1)

best_answer

As we have learnt

 

Charged Cylinder if P lies outside -

If Point P lies outside the cylinder

E_{out}=\frac{\lambda }{2\pi \varepsilon _{0}r}

V_{out}=\frac{-\lambda }{2\pi \varepsilon _{0}}\log_{e}r+c

- wherein

 

 For conducting and non conducting both when r > R

E = \frac{\lambda}{2\pi\epsilon_0r}

 


Option 1)

\frac{\lambda}{2\pi\epsilon_0 R}

Option 2)

\frac{\lambda}{2\pi\epsilon_0 }\log_e r + c

Option 3)

0

Option 4)

\frac{\lambda}{2\pi\epsilon_0 r}

Posted by

Avinash

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE