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Oxidation number of Carbon in  C_3O_2, Mg_2C_3 are respectively

  • Option 1)

    \frac{-4}{3},\frac{4}{3}

  • Option 2)

    \frac{4}{3},\frac{-4}{3}

  • Option 3)

    \frac{-2}{3},\frac{2}{3}

  • Option 4)

    \frac{-2}{3},\frac{4}{3}

 

Answers (1)

best_answer

As we learnt in 

Rules for Oxidation Number -

The algebraic sum of the oxidation number of all the atoms in a compound must be zero. In polyatomic ion the sum is equal to charge on the ion.

-

 

 Let's take the species individually,

C_{3}O_{2}, Let O.S of the Carbon be x

then, 3x-2(2)=0

x=4/3

and Mg_{2}C_{3}, let O.S of Carlean be y

2(2) + 3y=0

y=-4/3

\therefore Solution is 2


Option 1)

\frac{-4}{3},\frac{4}{3}

Incorrect

Option 2)

\frac{4}{3},\frac{-4}{3}

Correct

Option 3)

\frac{-2}{3},\frac{2}{3}

Incorrect

Option 4)

\frac{-2}{3},\frac{4}{3}

Incorrect

Posted by

Aadil

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