Oxidation number of Carbon in   are respectively Option 1) Option 2) Option 3) Option 4)

As we learnt in

Rules for Oxidation Number -

The algebraic sum of the oxidation number of all the atoms in a compound must be zero. In polyatomic ion the sum is equal to charge on the ion.

-

Let's take the species individually,

, Let O.S of the Carbon be x

then, 3x-2(2)=0

x=4/3

and , let O.S of Carlean be y

2(2) + 3y=0

y=-4/3

Solution is 2

Option 1)

Incorrect

Option 2)

Correct

Option 3)

Incorrect

Option 4)

Incorrect

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