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If n(U)=100,n(A)=30,n(B)=40 and n(A\cap B)= 10. Find n(A^{c}\cap B^{c})

  • Option 1)

    30

  • Option 2)

    40

  • Option 3)

    50

  • Option 4)

    60

 

Answers (1)

best_answer

As we learnt 

 

UNIVERSAL SET -

 

A set that contains all sets in a given context is called the “Universal Set”. The universal set is usually denoted by U, and all its subsets by the letters A, B, C, etc.

- wherein

R is the universal set of N,W and Z.

 

 n(A\cup B)= n(A)+n(B)-n(A\cap B)

n(A\cup B)= 30+40-10=60

n(A\cup B){}'= n\left ( A{}'\cap B{}' \right )= n\left ( U \right )-n(A\cap B)

                                                =100-60=40

 


Option 1)

30

Option 2)

40

Option 3)

50

Option 4)

60

Posted by

Himanshu

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