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  • Tell me? Some equipotential surface are shown in the figure. The magnitude and direction of the electric field is

Some equipotential surface are shown in the figure. The magnitude and direction of the electric field is

  • Option 1)

    100 V/m making angle 120o with the x-axis

  • Option 2)

    100 V/m making angle 60o with the x-axis

  • Option 3)

    200 V/m making angle 120o with the x-axis

  • Option 4)

    None of the above

 

Answers (1)

best_answer

 As we learned

 

For Positive charge -

Electric field line comes out.

- wherein

 

 By using dV=E dr \cos \theta suppose we consider line 1 and line 2 then

(30 – 20)= E cos 60^{\circ} (20 – 10)  \times 10^{-2}

 

 

So E=200 volt/m  making in angle 120o with x-axis


Option 1)

100 V/m making angle 120o with the x-axis

Option 2)

100 V/m making angle 60o with the x-axis

Option 3)

200 V/m making angle 120o with the x-axis

Option 4)

None of the above

Posted by

Plabita

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