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There is an electric field E in x-direction. If the work done in moving a charge 0.2 C through a distance of 2 metres along a line making an angle 60o with the x-axis is 4J, what is the value of E

  • Option 1)

    4 N/C

     

  • Option 2)

    8 N/C

  • Option 3)

    \sqrt{3}N/C

  • Option 4)

    20 N/C

 

Answers (1)

best_answer

As we learned

 

Relation between E and V in integral form -

\dpi{100} dV=-\int_{r_{1}}^{r_{2}}\overrightarrow{E}\cdot \vec{d}r=-\int_{r_{1}}^{r_{2}}Edr\cos \theta

-

 

 By using  W=q\times \Delta V  and \Delta V = E\Delta r\cos \theta

So,  W=qE\Delta r\cos \theta

W=4j=0.2\times E\times 2\times \cos 60

\Rightarrow E=20N/C


Option 1)

4 N/C

 

Option 2)

8 N/C

Option 3)

\sqrt{3}N/C

Option 4)

20 N/C

Posted by

Avinash

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