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Let ABC be a triangle whose circumcentre is at P. If the position vectors of A, B, C

and P are $\vec{a},\vec{b},\vec{c} \: \: and \: \: \frac{\vec{a}+\vec{b}+\vec{c}}{4}$

respectively, then the position vector of the orthocentre of this triangle, is :

Option 1)
$\vec{a}+\vec{b}+\vec{c}$

Option 2)
$-\left ( \frac{\vec{a}+\vec{b}+\vec{c}}{2} \right )$

Option 3)
$\vec{0}$

Option 4)
$\left ( \frac{\vec{a}+\vec{b}+\vec{c}}{2} \right )$

Answers (2)

best_answer

https://www.youtube.com/watch?v=y30g2lfwv_c

Posted by

Anurag Uikey

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