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  • The addition of dilute salt solution will give :Option: 1 Precipitate

The addition of dilute \mathrm{NaOH}$ to $\mathrm{Cr}^{3+} salt solution will give :
Option: 1 Precipitate of \mathrm{Cr}_{2} \mathrm{O}_{3} \left(\mathrm{H}_{2} \mathrm{O}\right)_{\mathrm{n}}
Option: 2 Precipitate of \mathrm{Cr}(\mathrm{OH})_{3}
Option: 3 Precipitate of \left[\mathrm{Cr}(\mathrm{OH})_{6}\right]^{3-}
Option: 4 A solution of \left[\mathrm{Cr}(\mathrm{OH})_{4}\right]^{-}

Answers (1)

best_answer

Addition of dilute \mathrm{NaOH} to a salt solution of \mathrm{Cr^{3+}} will lead to the formation of a precipitate of hydrated chromium (III) oxide.

\mathrm{Cr}^{3+}+\underset{\mathrm{dil}}{\mathrm{NaOH}} \longrightarrow \mathrm{Cr}_{2} \mathrm{O}_{3} \cdot \mathrm{nH}_{2} \mathrm{O}

Hence, the correct answer is option (1)

Posted by

sudhir.kumar

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