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The angular momentum of an electron in first orbit of Li++ ion is :

 

Option: 1

\frac{3\; h}{2\; \pi }        


Option: 2

\frac{9\; h}{2\; \pi }


Option: 3

\frac{h}{2\; \pi }


Option: 4

\frac{h}{6\; \pi }


Answers (1)

best_answer

 

Bohr quantisation principle -

mvr=\frac{nh}{2\pi } \\2\pi r= n\lambda

- wherein

Angular momentum of an electron in  stationary orbit is quantised.

 

 

Angular momentum (mvr) =n.\frac{h}{2\pi }

=\frac{h}{2\pi }\left ( n=1 \right )

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