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  • The aperture diameter of a telescope is 5m. The separation between the moon and the earth is . With light of wavelength of 5000 <img alt="\ov

The aperture diameter of a telescope is 5m. The separation between the moon and the earth is 4\times 10^5 km. With light of wavelength of 5000 \overset{o}{A}, the minimum separation between objects on the surface of moon, so that they are just resolved, is close to:
Option: 1 600 m
Option: 2 20 m
Option: 3 60 m
Option: 4 200 m
 

Answers (1)

best_answer

 

 

 

 

\theta = 1.22 \frac{\lambda}{a}

Distance = O_1O_2 = d\theta

                 = O_1O_2 = 1.22\frac{\lambda}{a}d

distance = O_1O_2 = \frac{1.22\times 5893\times 10^{-10}\times 4\times 10^8}{5}\approx 57.5m

Answer from the options = 60m 

Hence the correct option is (3). 

Posted by

avinash.dongre

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