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The average molar mass of chlorine is 35.5\: g\: mol^{-1}. The ratio of ^{35}Cl\; to\; ^{37}Cl in naturally occurring chlorine is close to :  
Option: 1 4:1
Option: 2 3:1
Option: 3 2:1
Option: 4 1:1

Answers (1)

best_answer

Given,

The average molar mass of chlorine is 35.5\: g\: mol^{-1}.

 

Let , the ratio of ^{35}Cl\; to\; ^{37}Cl in naturally occurring chlorine is close to x : y

 

Now, we know

\text { Av. molar mass }=\frac{\mathrm{n}_{1} \mathrm{M}_{1}+\mathrm{n}_{2} \mathrm{M}_{2}}{\left(\mathrm{n}_{1}+\mathrm{n}_{2}\right)}

So, 

35.5=\frac{x \times 35+y \times 37}{x+y}

1.5 y=-0.5 x

\frac{x}{y}=\frac{3}{1}

Therefore, the correct option is (2).

 

Posted by

Kuldeep Maurya

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