The average oxidation states of sulphur in and
are:
+1 and +3
+2 and + 1.5
+2 and +2.5
+2.5 and +3
Let x be the oxidation number of sulphur in?.
For a neutral compound, sum of oxidation states of all elements must be zero.
2+2x+3(−2)=0
2x=6−2
2x=4
x=+2
Suppose y be the oxidation number of sulphur in ?.
2+4y+3(−2)=0
4y=12−2
4y=10
y=+2.5
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