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  • The axes are translated so that the new equation of the circle <img alt="x^2 + y^2 - 5x + 2y - 5 = 0" src="https://learn.careers360.com/latex-image/?x%5E2%20&plus;%20y%5E2%20-%205x%20&plus;

The axes are translated so that the new equation of the circle x^2 + y^2 - 5x + 2y - 5 = 0 has no first degree terms. Then the new equation is

Option: 1

x^2 + y^2 = 9


Option: 2

x^2 + y^2 = 49/4


Option: 3

x^2 + y^2 = 81 /16


Option: 4

none 


Answers (1)

best_answer

 

Equation of a circle -

x^{2}+y^{2}=r^{2}

- wherein

Circle with centre \left ( O,O \right ) and radius r.

 

 

Equation of a circle -

\left ( x-h \right )^{2}+\left ( y-k \right )^{2}= r^{2}

- wherein

Circle with centre \left ( h,k \right ) and radius r.

 

 

x^2 + y^2 - 5x + 2y - 5 = 0 \\\\ (x-5/2 )^2 + (y+1)^2 - 5 - 25/4 -1 = 0 \\\\ ( x-5/2 )^2 + ( y +1)^2 = 49/4 

so the axes are shifted to (5/2,-1) New equation of circle must be 

x^2 + y^2 = 49/4

Posted by

seema garhwal

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