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  • The body is thrown horizontally from a point above the ground and the movement of the body is described by the equation  <img alt="x=\ 2t" src="https://entranceco

The body is thrown horizontally from a point above the ground and the movement of the body is described by the

equation  x=\ 2t ,  y\ =5t^2   , where x and y are the horizontal and vertical coordinates in metres after time

t. The beginning speed of the object is:

Option: 1

\sqrt{29}\frac{m}{s}  in the horizontal direction.


Option: 2

5\ \frac{m}{s} in the horizontal direction.


Option: 3

2\ \frac{m}{s}  in the vertical direction


Option: 4

2\ \frac{m}{s} In the horizontal direction.
 


Answers (1)

best_answer

The horizontal velocity of the projectile remains constant throughout the journey. Since the body is projected horizontally, the initial velocity will be the same as the horizontal velocity at any point.
Since, x=2t, \frac{d x}{d t}=2
Therefore Horizontal velocity =2 m/s
Initial velocity =2 m/s

 

Posted by

Rishi

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