Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The Born-Haler cycle for KCl is evaluated with the following data: $\mathrm{\Delta _{f}H^{\circleddash }for\, KCl= -436. 7\, kJ\, mol^{-1};\Delta _{sub}H^{\circleddash }for\, K= 89. 2\, kJ\, mol^{-1};}$ $\mathrm{\Delta_{\text {ionization }} H ^{\ominus} \text { for } K =419.0\ kJ\ mol ^{-1} ; \Delta_{\text {electron gain }} H ^{\ominus} \text { for } Cl _{( g )}=-348.6\ kJ\ mol ^{-1} \text {; }}$ $\mathrm{\Delta_{\text {bond }} H ^{\ominus} \text { for } Cl _{2}=243.0\ kJ\ mol ^{-1}}$ The magnitude of lattice enthalpy of KCl in kJ mol ^-1is _______(Nearest integer)

Answers (1)

best_answer

The Born Haber cycle is given as

Thus,

$\mathrm{89.2+419+121. 5-348-LE= -436. 7}$

$\mathrm{\therefore LE= 718.4}$

Hence,the answer is 718

Posted by

sudhir.kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

50 mL of 0.2 M ammonia solution is treated with 25 mL of 0.2 M HCl. If pK_b of ammonia solution is 4.75, the pH of the mixture will be :
Option: 1 3.75
Option: 2 4.75

Trending Articles/News

anam-khan

JEE Main 2025 January 22 shift 1, 2 unofficial answer keys out; question paper solutions

anam-khan

JEE Main 2025 January 22 Shift 2 Exam Analysis: Theory-based questions from chemistry, maths rated lengthy

anam-khan

NTA moves JEE Main 2025 to January 28, 29 for 114 candidates citing technical snag at Karnataka centre

Latest Question