Sum of these two vectros:
(2i+3j)+(2j+3k)=2i+(3+2)j+3k
=2i+5j+3k
So, component along x-direction: 2 units
&component along y-direction:5 units
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Given vectors = i. 2i + 3j , ii. 2j + 3k
Let , some of these given two vectors :
= ( 2i+ 3j ) + ( 2j + 3k )
=2i + (3 + 2)j + 3k
=2i + 5j + 3k
- Component along to ' x ' direction = 2
- Component along to ' y 'direction = 3