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  • The coordinates of an end-point of the latus-rectum of the parabola <img alt="\mathrm{(y-1)^2=4(x+1)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%28y-1%29%5E2%3D4%28x&am

The coordinates of an end-point of the latus-rectum of the parabola \mathrm{(y-1)^2=4(x+1)}  are
 

Option: 1

(0,-3)
 


Option: 2

(0,-1)


Option: 3

(0,1)


Option: 4

(1,3)


Answers (1)

best_answer

Shifting the origin at (−1, 1), we have \left.\begin{array}{l}\mathrm{x=X-1 }\\ \mathrm{y=Y+1}\end{array}\right\}

Using (i), the given parabola becomes \mathrm{Y^2=4 X}

The coordinates of the end-points of latus rectum are

\mathrm{(X=1, Y=2) \text { and }(X=1, Y=-2)}

Using (i), the coordinates of the end-points of the latus-rectum are (0,3) and (0,-1).

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Nehul

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