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  • The correct order of bond dissociation enthalpy of halogens is : Option: 1 <img alt="Cl_{2} > F_{2} > Br_{2} >I_{2}" src="https://entrancecorner.codecogs.com/gif.latex?Cl_%7B2%7D%20%3E%20F_%7B2%7D%20%3E%20Br_%7B2%7D%20%

The correct order of bond dissociation enthalpy of halogens is :
Option: 1 Cl_{2} > F_{2} > Br_{2} >I_{2}
 
Option: 2 I_{2} > Br_{2} > Cl_{2} > F_{2}
Option: 3 Cl_{2} > Br_{2} > F_{2} > I_{2}  
Option: 4 F_{2} > Cl_{2} > Br_{2} > I_{2}

Answers (1)

best_answer

F2 has an F-F bond, F2 involves repulsion of non-bonding electrons & moreover its size is small & hence due to high repulsion of the electron cloud of F. It's bond dissociation energy in very low but not less than I2.

So correct order of bond dissociation enthalpy of halogens is 

\mathrm{Cl_{2} > Br_{2} > F_{2} > I_{2}}

Therefore, option(3) is correct.

Posted by

sudhir.kumar

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