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The current flowing in a coil is 3 A and the power consumed is 108 W.If the a.c. source is of 120 V,50 Hz , the resistance of the circuit is ;

Option: 1

\mathrm{24 \Omega}


Option: 2

\mathrm{10 \Omega}


Option: 3

\mathrm{12 \Omega}


Option: 4

\mathrm{6 \Omega}


Answers (1)

best_answer

\mathrm{\text { From } P=1^2 R, R=\frac{P}{I^2}=\frac{108}{3^2}=12 \Omega}

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Gaurav

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