Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The diffusion coefficient of an Ideal was is Proportional to its mean free Path and mean speed. The absolute Temperature at an ideal gas is increased 8 time and its pressure 4 time. As a result, th

The diffusion coefficient of an Ideal was is Proportional to its mean free Path and mean speed. The absolute Temperature at an ideal gas is increased 8 time and its pressure 4 time. As a result, the diffusion coefficient ot this gas increase A time. The value of A is -

Option: 1

4


Option: 2

2


Option: 3

8


Option: 4

10


Answers (1)

best_answer

Rate of diffusion \mathrm{\alpha \lambda \propto U_{A v g}}
\mathrm{ \alpha \frac{1}{\sqrt{2} \pi \sigma^2 N^*} \times \operatorname{U_{Avg}} }
\mathrm{ \alpha \frac{1}{\sqrt{2} \pi \sigma^2 N^*} }
\mathrm{ \alpha \frac{\operatorname{U_{Avg}}(K T)}{\sqrt{2} n \sigma^2 P} }

Rate of diffuaion \mathrm{\alpha \frac{T^{3 / 2}}{p}}
\mathrm{ \frac{{r_{final}}}{{ r_{inital} }}=\frac{(8)^{3 / 2}}{(4)}=2 }

 

Posted by

admin

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

FIITJEE blames managing partners for shutdown, warns legal action against poaching of staff
anam-khan

First 3 days of JEE Main 2025: Exam paper analysis, postponement, technical glitches
anam-khan

NTA changes JEE Main 2025 exam centre in Ayodhya due to Maha Kumbh gathering

Latest Question