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  • The eccentricity of the conjugate hyperbola of the hyperbola <img alt="\mathrm{49 x^2-81 y^2=3969}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B49%20x%5E2-81%20y%5E2%3D3969%7D"

The eccentricity of the conjugate hyperbola of the hyperbola \mathrm{49 x^2-81 y^2=3969} is

Option: 1

2.55


Option: 2

1.62


Option: 3

3.66


Option: 4

7.11


Answers (1)

best_answer

 The given hyperbola is \mathrm{\frac{x^2}{81}-\frac{y^2}{49}=1}
Its eccentricity e is given by \mathrm{49=81\left(e^2-1\right)}

Hence, eccentricity \ell^{\prime} of the conjugate hyperbola is given by

\mathrm{81=49\left(e^{\prime 2}-1\right) \text { or } e^{\prime 2}=\frac{130}{49} \text { or } e^{\prime}=\frac{\sqrt{130}}{7}=1.62}
 

Posted by

HARSH KANKARIA

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