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The energy required to ionised a hydrogen like ion in its ground state is 9 Rydbergs. What is the wavelength (in nm) of the radiation emitted when the electron in this ion jumps from the second excited state to the ground state ?
Option: 1 11.4
Option: 2 24.2
Option: 3 8.6
Option: 4 35.8
 

Answers (1)

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\frac{hc}{\lambda }=(13.6eV)z^{2}\left [ \frac{1}{n^{2}_{1}}-\frac{1}{n^{2}_{2}} \right ]

n_{1}=1

n_{2}=3

\frac{hc}{\lambda }=(13.6eV)(3^{2})\left [ \frac{1}{1^{2}}-\frac{1}{3^{2}} \right ]

\Rightarrow \frac{hc}{\lambda }=(13.6eV)(9)\left ( \frac{8}{9} \right )

Wavelength=\frac{1240}{8\times 13.6}nm

{\lambda }=11.40nm

Hence the correct option is (1).

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avinash.dongre

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