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  • The equation of a line perpendicular to the line x a y b 1 and passing through the point where it meets x axis is

The equation of a line perpendicular to the line x/a -y/b =1 and passing through the point where it meets x axis is

Answers (1)

@Shekhar suman

The equation of a line perpendicular to the line x/a -y/b =1 and passing through the point where it meets x axis is

slope of given line is b/a so the slope of perpendicular line is -a/b

so required line is y=\frac{-ax}{b}+c\\ c\ can \ be\ obtained\ by\ given\ condition

given perpendicular line passes through (a,0) 

c=\frac{b}{a^2}c=\frac{b}{a^2}\\ so\ the\ line\ is \ y=\frac{-ax}{b}+\frac{b}{a^2}

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Safeer PP

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