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  • The equilibrium constant at 298 K for a reaction A+BC+D is 100.  If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L−1) will be : Option: 1 &nbs

The equilibrium constant at 298 K for a reaction A+BC+D is 100.  If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L−1) will be :
Option: 1  0.182  
Option: 2  0.818  
Option: 3  0.818  
Option: 4  1.182  
 

Answers (1)

best_answer

As we dicussed in the concept

Law of Chemical equilibrium -

At a given temperature, the product of concentration of the reaction products raised to the respective stoichiometric coefficient in the balanced chemical equation divided by the product of concentration of the reactants raised to their individual stoichiometric coefficients has a constant value.

- wherein

aA+bB\rightleftharpoons cC+dD


K_{c}=\frac{[C]^{c\:[D]^{d}}}{[A]^{a}\:[B]^{b}}

[A],\:[B],\:[C]\:[D]

are equilibrium concentration

 

 For reaction              A+B\rightleftharpoons C+D

Initial concentration IM      IM       IM       IM

At equilibarium if degree of dissociation is A+B\rightleftharpoons C+D\alpha then

A+B\rightleftharpoons C+D

1-\alpha   1-\alpha      H\alpha   1+\alpha

K_{c}=\frac{(1+\alpha)^{2}}{(1-\alpha)^{2}}=100

10=\frac{1+\alpha}{1-\alpha }

10-10\alpha =1+\alpha

9=11\alpha

\alpha =\frac{9}{11}

Concentration of D is 1+\alpha=I+\frac{9}{11}

=1.818

Posted by

Ritika Jonwal

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