Get Answers to all your Questions

header-bg qa

The expected graphical representation of the variation of angle of deviation '\delta' with angle of incidence 'i' in a prism is :
Option: 1
Option: 2
Option: 3
Option: 4

Answers (1)

best_answer

\delta =i+e-A

First refraction,

\mu_{1} \sin i=\mu_{2} \sin r_{1} \rightarrow1

Second refraction,

\mu_{2} \sin r_{2}=\mu_{1}$ sine $\rightarrow 2

A=r_{1}+r_{2} \rightarrow 3

Angle \: \: of \: \: deviation =\delta =i+e-A

\begin{aligned} &\delta=i+\sin ^{-1}\left(\mu_{2}^{\prime} \sin \left(r_{2}\right)\right)-A \\ &\delta=i+\sin ^{-1}\left(\mu_{2}^{\prime} \sin \left(A-r_{1}\right)\right)-A \end{aligned}
As i increases, r_{1} also increares which in tern reduces \left(A-r_{1}\right)
\therefore \delta \text { decreases }

At\: i\rightarrow 0,\delta \rightarrow max

Also when r_{1}=r_{2}, \quad i=e

at that point \delta will be minimum

Hence,the correct option is (2)

Posted by

vishal kumar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE