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The 'f' orbitals are half and completely filled, respectively in lanthanide ions 

\mathrm{\text { [Given : Atomic no. Eu, 63; } \mathrm{Sm}, 62 ; \mathrm{Tm}, 69 ; \mathrm{Tb}, 65 ; \mathrm{Yb}, 70 ; \mathrm{Dy}, 66]}

Option: 1

\mathrm{Eu}^{2+} \text { and } \mathrm{Tm}^{2+}


Option: 2

\mathrm{Sm}^{2+} \text { and } \mathrm{Tm}^{3+}


Option: 3

\mathrm{Tb}^{4+} \text { and } \mathrm{Yb}^{2+}


Option: 4

\mathrm{Dy}^{3+} \text { and } \mathrm{Yb}^{3+}


Answers (1)

best_answer

The ions having fully filled or half filled ' f ' orbital configuration are

\begin{aligned} &\mathrm{T b^{4+}:\left[Xe\right] 4 f^{7} }\\ &\mathrm{Y b^{2+}:[X e] 4 f^{14}} \end{aligned}

Hence, Option (3) is correct.

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Nehul

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