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  • The given potentiometer has its wire of resistance . When the sliding contact is in the middle of the potentiometer wire, the potential drop across <img alt="2 \Omega

The given potentiometer has its wire of resistance 10 \Omega. When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2 \Omega resistor is :
Option: 1 10V
Option: 2 5V
Option: 3 \frac{40}{9}V
Option: 4 \frac{40}{11}V

Answers (1)

best_answer


I= \frac{20}{5+\frac{10}{7}}= \frac{140}{45}
V_{AJ}= I\left ( R_{AJ} \right )= \frac{{140}}{{45}}\times \frac{10}{{7}}
                                = \frac{200}{45}= \frac{40}{9}V
The correct option is (3)

Posted by

vishal kumar

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