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  • The half - life of a radioactive element A is the same as the mean-life of another radioactive element B. Initially both substances have the same number of atoms, then : <div class='qna-op

The half - life of a radioactive element A is the same as the mean-life of another radioactive element B. Initially both substances have the same number of atoms, then : 

Option: 1

A and B both decay at the same rate always 


Option: 2

A and B will decay at the same rate initially 


Option: 3

A will decay at a faster rate than B initially 


Option: 4

B will decay at a faster rate than A initially 


Answers (1)

best_answer

\begin{aligned} &\left(T_{1 / 2}\right)_{A}=\left(T_{\text {mean}}\right)_{B}\\ &\Rightarrow \frac{0.693}{\lambda_{A}}=\frac{1}{\lambda_{B}} \Rightarrow \lambda_{A}=0.693\times\lambda_{B} \\ &\text { or } \lambda_{A}<\lambda_{B} \end{aligned}
 

Also rate of decay =λN
Initially number of atoms (N) of both are equal but since λB>λA, therefore B will decay at a faster rate than A

Posted by

Devendra Khairwa

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