# Screenshot_550.png The height at which the acceleration due to gravity becomes ( where g = the acceleration due to gravity on the surface of the earth ) in terms of R, the radius of the earth is

@Santhosh

The accelerator due to gravity at a height h from the earth given as $\frac{g}{9}$

$\frac{GM}{r^{2}}=\frac{GM}{R^{2}} \frac{1}{9}$

$r=3R$

The height above the ground is 2R.

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