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  • The image of the point (3,5) in the line , lies on :   Option: 1 <img alt="\left ( x-2 \right )^{2}+\left ( y-4 \right )^{2}

The image of the point (3,5) in the line x-y+1=0, lies on :
 
Option: 1 \left ( x-2 \right )^{2}+\left ( y-4 \right )^{2}=4
Option: 2 \left ( x-2 \right )^{2}+\left ( y-2 \right )^{2}=12
Option: 3 \left ( x-4 \right )^{2}+\left ( y+2 \right )^{2}=16
Option: 4 \left ( x-4 \right )^{2}+\left ( y-4 \right )^{2}=8

Answers (1)

best_answer

 

\begin{aligned} &\frac{x-3}{1}=\frac{y-5}{-1}=-2\left(\frac{3-5+1}{1+1}\right)\\ &\text { So, } x=4, y=4\\\\ &\text {Hence, }(x-2)^{2}+(y-4)^{2}=4 \end{aligned}

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Suraj Bhandari

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