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The integral of \int4^{x}dx is

Option: 1

4^{x}+C


Option: 2

4^{x}\log\ 4+C


Option: 3

\frac{\log\ 4}{4^{x}}+c


Option: 4

\frac{4^{x}}{\log\ 4}+c


Answers (1)

best_answer

Given that,

\int4^{x}dx

Using the integral formula,

\int a^{x}dx=\frac{a^{x}}{\log\ a}+c

Therefore,

\int 4^{x}dx=\frac{4^{x}}{\log\ 4}+c

Posted by

Gautam harsolia

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