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  • The intensity of gamma radiation from a given source is . On passing through 36 mm of lead  it is reduced to . The thickness of

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Answers (2)

Absorption of x ray -

I=I_{0}\cdot e^{-2\mu x} 

- wherein

x = thickness of material

\mu = absorption coefficient

 

 

 I=I_{0}.e^{-\mu x}

\frac{I}{8}=I_{0}.e^{-\mu(36mm)}

e^{-36\mu}=\frac{1}{8}                                   ..................(1)

\frac{I_{0}}{2}=I_{0}e^{-\mu x}

e^{-\mu x}=\frac{1}{2}= \left(\frac{1}{8} \right )^{1/3}

From equation (1)

 e^{-\mu x}=e^{-12\mu}

Hence,  x = 12 mm

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Safeer PP

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 Since Intensity (I)\alpha\frac{1}{r^{2}}

When distance become half intensity becomes 4 times

Hence number of electrons increases by factor of 4.

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Safeer PP

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