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The ion that cannot be precipitated by both HCl and H2S is

Option: 1

Pb^{2+}


Option: 2

Cu^{+}


Option: 3

Ag^{+}


Option: 4

Sn^{+2}


Answers (1)

best_answer

Test of Sulfide ion -

Add a Sodium nitroprusside solution in an alkaline midium

Na_2S + Na_2(Fe(CN)_5NO) \overset{NaOH}{\rightarrow} Na_4(Fe(CN)_6 NOS) \: Purple

- wherein

Purple color confirm the presence of  S^{2-}

-

The ion that cannot be precipitated by both HCl and H2S is Sn2+, while all others are precipitated by H2S in the presence of HCl. Sn2+ cannot be precipitated by HCl, but is precipitated by H2?S as a chocolate-colored precipitate.

Therefore, Option(4) is correct.

Posted by

Gaurav

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