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The molality of a 10 \%(\mathrm{v} / \mathrm{v}) solution of di-bromine solution in \mathrm{CCl}_4 (carbon tetrachloride) is ' x{ }^{\prime}.
$$ x= _____________ \times 10^{-2} \mathrm{M}. (Nearest integer)
[Given : molar \, \, mass \, \, of \, \, \mathrm{Br}_2=160 \mathrm{~g} \mathrm{~mol}^{-1}
$$ \begin{aligned} & \text { atomic mass of } \mathrm{C}=12 \mathrm{~g} \mathrm{~mol}^{-1} \\ & \text { atomic mass of } \mathrm{Cl}=35.5 \mathrm{~g} \mathrm{~mol}^{-1} \\ & \text { density of dibromine }=3.2 \mathrm{~g} \mathrm{~cm}^{-3} \\ & \text { density of } \left.\mathrm{CCl}_4=1.6 \mathrm{~g} \mathrm{~cm}^{-3}\right] \end{aligned}

Option: 1

139


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

 (10 \mathrm{ml} \text { solute in } 90 \mathrm{ml} \text { solvent }
mass of solute =10 \times 3.2=32 \mathrm{~g}
mass of solvent =90 \times 1.6 \mathrm{~g}
\mathrm{m}=\frac{32 \times 1000}{160 \times 90 \times 1.6}=1.388
\mathrm{m}=138.8 \times 10^{-2}=139

Posted by

Pankaj Sanodiya

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