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  • The momentum of a photon of energy 1 MeV in Kg m/s. will beOption: 1 <img alt="0.33\times 10^{6}" src="https://learn.careers360.com/latex-image/?0.33

The momentum of a photon of energy 1 MeV in Kg m/s. will be

Option: 1

0.33\times 10^{6}

 




 


Option: 2

7\times 10^{-24}


Option: 3

10^{-22}


Option: 4

5\times 10^{-22}


Answers (1)

As we learned

 

 

 

 E=mc^{2}

or p=mc=\frac{E}{C}

p=\frac{10^{+6}\times 1\cdot 6\times 10^{-19}J}{3\times 10^{8}}=0.53\times 10^{-21}

p=5.3\times 10^{-22}

 

Posted by

Ramraj Saini

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